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प्रश्न
Find the square of `"a"+1/(5"a")`
बेरीज
उत्तर
`("a"+1/(5"a"))^2=("a")^2+(1/(5"a"))^2+2xx"a"xx1/(5"a")`
`="a"^2+1/(25"a"^2)+2/5`
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