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Find the square of the given number. 32 - Mathematics

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प्रश्न

Find the square of the given number.

32

बेरीज

उत्तर

322 = (30 + 2)2

= 30 (30 + 2) + 2 (30 + 2)

= 302 + 30 × 2 + 2 × 30 + 22

= 900 + 60 + 60 + 4

= 1024.

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पाठ 6: Squares and Square Roots - Exercise 6.2 [पृष्ठ ९८]

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एनसीईआरटी Mathematics [English] Class 8
पाठ 6 Squares and Square Roots
Exercise 6.2 | Q 1.1 | पृष्ठ ९८

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संबंधित प्रश्‍न

What will be the units digit of the square of the following number?

52


Observe the following pattern 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) = \frac{2 \times 3 \times 4}{3}\] 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) + \left( 3 \times 4 \right) = \frac{3 \times 4 \times 5}{3}\] 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) + \left( 3 \times 4 \right) + \left( 4 \times 5 \right) = \frac{4 \times 5 \times 6}{3}\] 

and find the value of(1 × 2) + (2 × 3) + (3 × 4) + (4 × 5) + (5 × 6)


Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :  

52 + 62 + 72 + 82 + 92 + 102 + 112 + 122

 

 


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Write a Pythagorean triplet whose smallest member is 8.

The sum of first n odd natural numbers is ______.


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