Advertisements
Advertisements
प्रश्न
Find the sum of a2 − ab + bc, 2ab + bc − 2a2 and − 3bc + 3a2 + ab.
उत्तर
(a2 − ab + bc) + (2ab + bc − 2a2) + (− 3bc + 3a2 + ab)
= a2 − ab + bc + 2ab + bc − 2a2 − 3bc + 3a2 + ab
= a2 + 3a2 − 2a2 + 2ab + ab − ab + bc + bc − 3bc
= 4a2 − 2a2 + 3ab − ab + 2bc − 3bc
= 2a2 + 2ab − bc
APPEARS IN
संबंधित प्रश्न
Subtract the first term from the second:
4ab, 6ba
Add the following expression:
− x2 − 3xy + 3y2 + 8, 3x2 − 5y2 − 3 + 4xy and − 6xy + 2x2 − 2 + y2
Evaluate:
(8a + 15b) − (3b − 7a)
Subtract:
5 − a − 4b + 4c from 5a − 7b + 2c.
From the sum of x + y – 2z and 2x – y + z subtract x + y + z.
The sum of two expressions is 5x2 – 3y2. If one of them is 3x2 + 4xy – y2, find the other.
The sum of two expressions is 3a2 + 2ab – b2. If one of them is 2a2 + 3b2, find the other.
Fill in the blank:
5 × 5a3 = ................
Fill in the blank:
6 × 6x2 × 6x2y2 = ...................
Fill in the blank:
5x × 2x2y × (− 7y3) × 2x3y2 = ...............
