Advertisements
Advertisements
प्रश्न
Find the sum of the A.P., 14, 21, 28, ......, 168.
उत्तर
Here a = 14 , d = 7 and tn = 168
tn = a + (n – 1)d
`=>` 168 = 14 + (n – 1)7
`=>` 154 = 7n – 7
`=>` 154 = 7n – 7
`=>` 161 = 7n
`=>` n = 23
We know that,
`S_n = n/2 [2a + (n - 1)d]`
`=> S_23 = 23/2 [2 xx 14 + (23 - 1)7]`
= `23/2 (28 + 154)`
= `23/2 xx 182`
= 2093
Therefore, the sum of the A.P., 14, 21, 28, ......, 168 is 2093.
APPEARS IN
संबंधित प्रश्न
Find three numbers in A.P. whose sum is 24 and whose product is 440.
The sum of three consecutive terms of an A.P. is 21 and the sum of their squares is 165. find these terms.
The angles of a quadrilateral are in A.P. with common difference 20°. Find its angles.
The sum of three numbers in A.P. is 15 and the sum of the squares of the extreme terms is 58. Find the numbers.
Q.6
Find the sum of last 8 terms of the A.P. –12, –10, –8, ……, 58.
Find the sum of the two middle most terms of the A.P. `-(4)/(3), -1, -(2)/(3),...,4(1)/(3)`
If the seventh term of an A.P. is `(1)/(9)` and its ninth term is `(1)/(7)`, find its 63rd term.
The 15th term of an A.P. is 3 more than twice its 7th term. If the 10th term of the A.P. is 41, find its nth term.
The sum of the first three terms of an A.P.is 33. If the product of the first and the third terms exceeds the second term by 29, find the A.P.