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प्रश्न
Find the value of `(64/125)^((-2)/3)`
बेरीज
उत्तर
`(64/125)^((-2)/3) = (4^3/5^3)^((-2)/3)`
= `[(4/5)^3]^((-2)/3)`
= `(4/5)^(3 xx (-2)/3)`
= `(4/5)^(-2)`
= `(4^(-2))/(5^(-2))`
= `(5^2)/(4^2)`
= `25/16`
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Fractional Index
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Real Numbers - Exercise 2.5 [पृष्ठ ५९]
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