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प्रश्न
Find the value of θ in the given figure.
पर्याय
`sin^-1(2/sqrt3)`
`sin^-1(1/sqrt3)`
`sin^-1(1/2)`
`sin^-1(1/sqrt2)`
MCQ
रिकाम्या जागा भरा
उत्तर
`bb(sin^-1(1/sqrt3))`
Explanation:
For total internal reflection, μ = `1/sin"c"`
where, C = critical angle
Condition for TIR, the angle of incidence must be greater than critical angle C,
(90 - θ1) > C
sin (90 - θ1) > sinC
cosθ1 = `1/mu`
cosθ1 > `1/(2//sqrt3)`
cosθ1 > `sqrt3/2`
θ1 > 30°
According to Snell’s law,
μ1sinθ = μ2sinθ1
1sinθ = `2/sqrt3`sinθ1
sinθ = `2/sqrt3`sin30°
sinθ = `1/sqrt3`
So, θ = `sin^-1(1/sqrt3)`
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