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Find the value of k, if the area of triangle whose vertices are P(k, 0), Q(2, 2), R(4, 3) is 32sq.unit - Mathematics and Statistics

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प्रश्न

Find the value of k, if the area of triangle whose vertices are P(k, 0), Q(2, 2), R(4, 3) is `3/2 "sq.unit"`

बेरीज

उत्तर

Here, P(x1, y1) ≡ P(k, 0), Q(x2, y2) ≡ Q(2, 2), R(x3, y3) ≡ R(4, 3)

A(ΔPQR) = `3/2 "sq.units"`

Area of a triangle = `1/2|(x_1, y_1, 1),(x_2, y_2, 1),(x_3, y_3, 1)|`

∴ `± 3/2 = 1/2|("k", 0, 1),(2, 2, 1),(4, 3, 1)|`

∴ `± 3/2 = 1/2["k"(2 - 3) - 0 + 1(6 - 8)]`

∴ `± 3/2 = 1/2(-"k" - 2)`

∴ ± 3 = –k – 2

∴ 3 = –k – 2 or –3 = –k – 2

∴ k = – 5 or k = 1

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Application of Determinants - Area of Triangle and Collinearity of Three Points
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Determinants and Matrices - Exercise 4.3 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board
पाठ 4 Determinants and Matrices
Exercise 4.3 | Q 7 | पृष्ठ ७५

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