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प्रश्न
Find the value of the following:
tan 54° 26′
उत्तर
0' | 6' | 12' | 18' | 24' | 30' | 36' | 42' | 48' | 54' | Mean difference | ||||||||
0.0° | 0.1° | 0.2° | 0.3° | 0.4° | 0.5° | 0.6° | 0.7° | 0.8° | 0.9° | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | |
49 | 0.7547 |
From the natural tangents table
tan 54° 24′ = 1.3968
Mean difference 2' = 17
tan 54° 26′ = 1.3985
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