Advertisements
Advertisements
प्रश्न
Find the value(s) of p in (i) to (iv) and p and q in (v) for the following pair of equations:
2x + 3y – 5 = 0 and px – 6y – 8 = 0,
if the pair of equations has a unique solution.
उत्तर
Given pair of linear equations is
2x + 3y – 5 = 0
px – 6y – 8 = 0
On comparing with ax + by + c = 0, we get
Here, a1 = 2, b1 = 3, c1 = – 5
And a2 = p, b2 = – 6, c2 = – 8
`a_1/a_2 = 2/p`
`b_1/b_2 = - 3/6 = -1/2`
`c_1 /c_2 = 5/8`
Since the pair of linear equations has a unique solution,
`a_1/a_2 ≠ b_1/b_2`
So `2/p ≠ -1/2`
p ≠ – 4
Hence, the pair of linear equations has a unique solution for all values of p except – 4.
APPEARS IN
संबंधित प्रश्न
Find the value of k for which each of the following systems of equations has infinitely many solutions :
2x + 3y − 5 = 0
6x + ky − 15 = 0
Find the value of k for which each of the following system of equations has infinitely many solutions :
2x + (k - 2)y = k
6x + (2k - 1)y - (2k + 5)
Find the values of a and b for which the following system of equations has infinitely many solutions:
2x - (2a + 5)y = 5
(2b + 1)x - 9y = 15
Find the values of a and b for which the following system of equations has infinitely many solutions:
(a - 1)x + 3y = 2
6x + (1 + 2b)y = 6
Solve for x and y:
0.4x + 0.3y = 1.7, 0.7x – 0.2y = 0.8.
Solve for x and y:
7(y + 3) – 2(x + 2) = 14, 4(y – 2) + 3(x – 3) = 2
Find the value of k for which the system of linear equations has an infinite number of solutions.
2x + 3y – 7 = 0,
(k – 1)x + (k + 2)y=3k
If the point of intersection of ax + by = 7 and bx + ay = 5 is (3,1), then find the value of a and b.
If 217x + 131y = 913, 131x + 217y = 827, then x + y is ______.
Find the value(s) of p in (i) to (iv) and p and q in (v) for the following pair of equations:
– 3x + 5y = 7 and 2px – 3y = 1,
if the lines represented by these equations are intersecting at a unique point.