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प्रश्न
Find the values of the following polynomials at a = –2 and b = 3:
a3 + 3a2b + 3ab2 + b3
उत्तर
Given, a = –2 and b = 3
So, putting a = –2 and b = 3 in the given expressions, we get
a3 + 3a2b + 3ab2 + b3 = (–2)3 + 3(–2)2(3) + 3(–2)(3)2 + (3)3
= –8 + 36 – 54 + 27
= 1
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