Advertisements
Advertisements
प्रश्न
Find two consecutive positive even integers whose squares have the sum 340.
उत्तर
Let two consecutive positive even integers be 2x, 2x + 2
∴ (2x)2 + (2x + 2)2 = 340
⇒ 4x2 + 4x2 + 4 + 8x = 340
⇒ 8x2 + 8x - 336 = 0
⇒ x2 + x - 42 = 0
⇒ x2 + 7x - 6x - 42 = 0
⇒ x(x + 7) -6(x + 7) = 0
⇒ (x + 7) (x + 6) = 0
⇒ x + 7 = 0 or x - 6 = 0
⇒ x = -7 or x = 6
Negative integer is not required, therefore, x = 6.
Hence, integers are 6 x 2, (6 x 2)+ 2.
i.e., 12 and 14.
APPEARS IN
संबंधित प्रश्न
Find the roots of the following quadratic equation by factorisation:
100x2 – 20x + 1 = 0
The product of Shikha's age five years ago and her age 8 years later is 30, her age at both times being given in years. Find her present age.
Some students planned a picnic. The budget for food was Rs. 480. But eight of these failed to go and thus the cost of food for each member increased by Rs. 10. How many students attended the picnic?
Solve x2 – 4x – 12 =0; when x ∈ I
The sum of the squares to two consecutive positive odd numbers is 514. Find the numbers.
If y = 1 is a common root of the equations \[a y^2 + ay + 3 = 0 \text { and } y^2 + y + b = 0\], then ab equals
Solve equation using factorisation method:
x(x – 5) = 24
A two digit number is such that the product of its digit is 14. When 45 is added to the number, then the digit interchange their places. Find the number.
Solve the following equation by factorization
`(x - 3)/(x + 3) + (x + 3)/(x - 3) = 2(1)/(2)`
If `x + 1/x = 2.5`, the value of x is ______.