मराठी

Find the Value of P, If the Mean of the Following Distribution is 20. X: 15 17 19 20+P 23 F: 2 3 4 5p 6 - Mathematics

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प्रश्न

Find the value of p, if the mean of the following distribution is 20. 

x: 15 17 19 20+p 23
f: 2 3 4 5p 6
थोडक्यात उत्तर

उत्तर

The given data in tabulated form is

15 17 19 20+p 23
2 3 4 5p 6

We have to find the value of p using the information that the mean of the data is 20.

Prepare the following frequency table of which the first column consists of the values of the variate and the second column the corresponding frequencies. Multiply the frequency of each row with the corresponding values of variable to obtain the third column containing `f_ix_i`.

`x_i`  `f_i` `f_ix_i`
15 2 30
17 3 51
19 4 76
20+p 5p 5p(20+p)
23 6 138

Find the sum of all entries in the second and third column to obtain and `sum f_ix_I` respectively. Therefore,

` N = sum_(i=1)^5 f_i`

      = 2+3+4+5p+6

      =15+5p

`   sum_(i=1)^5 f_ix`

=30+51+76+5p(20+p)+138

=5p+ 100p +295

The mean is

`bar(X) = (sum_(i=1)^5 f_ix_i)/N`

`=(5p^2 +100p+295)/(15+5p)`

Hence, we have

`=(5p^2 +100p+295)/(15+5p)=20`

⇒5p+ 100p +295=300+100p

⇒5p2 = 300-295 

⇒ 5p= 5

⇒ p=`5/5`

⇒ p= 1

`⇒ p =+- 1`

If p is negative then the 4th frequency becomes negative. But frequency can’t be negative. Hence the possible value of is 1

p = 1

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पाठ 24: Measures of Central Tendency - Exercise 24.2 [पृष्ठ १५]

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आरडी शर्मा Mathematics [English] Class 9
पाठ 24 Measures of Central Tendency
Exercise 24.2 | Q 10 | पृष्ठ १५

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