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प्रश्न
For a particle performing SHM when displacement is x, the potential energy and restoring force acting on it is denoted by E and F, respectively. The relation between x, E and F is ____________.
पर्याय
`"E"/"F" + "x" = 0`
`(2"E")/"F" + "x" = 0`
`(2"E")/"F" - "x" = 0`
`"E"/"F" - "x" = 0`
उत्तर
For a particle performing SHM when displacement is x, the potential energy and restoring force acting on it is denoted by E and F, respectively. The relation between x, E and F is `underline((2"E")/"F" + "x" = 0)`.
Explanation:
The restoring force acting on the particle in SHM,
F = −kx ...............(i)
The potential energy in SHM, E = `1/2 "kx"^2` ....(ii)
From Eqs. (i) and (ii), we get
E = `1/2 xx ((-"F")/"x") xx "x"^2 = -("Fx")/2`
or `(2"E")/"F"` = −x or `(2"E")/"F" + "x"` = 0