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प्रश्न
For adsorption of gas over solid surface following data is obtained at 300 K.
Pressure of gas (mm of Hg) |
100 | 25 |
Amount adsorged per kg of charcoal |
3 gm | 1.5 gm |
The slope of the graph between log P vs log x/m will be ______.
[x/m and P are in same units as given in question.]
पर्याय
1
0
2
5
MCQ
रिकाम्या जागा भरा
उत्तर
The slope of the graph between log P vs log x/m will be 2.
Explanation:
`log x/m = log "K" + 1/"n" log "P"`
log P = n log `x/m` + log K
`3/1.5 = ("K" (100)^(1//"n"))/("K"(25)^(1//"n"))`
2 = 22/n
`=> 2/"n" = 1`
⇒ n = 2
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Adsorption
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