मराठी

For adsorption of gas over solid surface following data is obtained at 300 K. The slope of the graph between log P vs log x/m will be ______. -

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प्रश्न

For adsorption of gas over solid surface following data is obtained at 300 K.

Pressure of gas
(mm of Hg)
100 25
Amount adsorged
per kg of charcoal
3 gm 1.5 gm

The slope of the graph between log P vs log x/m will be ______.

[x/m and P are in same units as given in question.]

पर्याय

  • 1

  • 0

  • 2

  • 5

MCQ
रिकाम्या जागा भरा

उत्तर

The slope of the graph between log P vs log x/m will be 2.

Explanation:

`log  x/m = log "K" + 1/"n"  log "P"`

log P = n log `x/m` + log K

`3/1.5 = ("K" (100)^(1//"n"))/("K"(25)^(1//"n"))`

2 = 22/n

`=> 2/"n" = 1`

 ⇒ n = 2

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Adsorption
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