Question

For the reaction 

2N₂O₅ (g) → 4NO₂ (g) + O₂ (g), the rate of formation of NO₂ (g) is 2·8 × 10^–3 M s^–1. Calculate the rate of disappearance of N₂O₅ (g).

Answer 1

A rate of formation of NO₂ = 2·8 × 10^–3 M s^–1

A rate of Disappearance of N₂O₅ = 

`- 1/2 (d[N_2O_5])/(dt) = 1/4 (d[NO_2])/(dt)`

`(d[N_2O_5])/(dt) = 1/4 xx 2.8 xx 10^(-3) xx 2 = 1.4 xx 10^(-3)`

`= 1.4 xx 10^(-3) Ms^(-1)`