Advertisements
Advertisements
प्रश्न
For the G.P., if r = `1/3`, a = 9, find t7.
उत्तर
Given, r = `1/3`, a = 9
tn= arn–1
∴ t7 = `9 xx (1/3)^(7 - 1)`
= `9xx(1/3)^6`
= `9xx1/729`
∴ t7 = `1/81`
APPEARS IN
संबंधित प्रश्न
Verify whether the following sequence is G.P. If so, write tn:
2, 6, 18, 54, ...
Verify whether the following sequence is G.P. If so, write tn:
1, – 5, 25, – 125, ...
Verify whether the following sequence is G.P. If so, write tn:
3, 4, 5, 6, ...
Verify whether the following sequence is G.P. If so, write tn:
7, 14, 21, 28, ...
For the G.P., if a = `7/243, "r" = 1/3`, find t3.
Insert two numbers between 1 and – 27 so that the resulting sequence is a G.P.
For a G.P. a = `4/3 and "t"_7 = 243/1024`, find the value of r.
Find five numbers in G.P. such that their product is 243 and sum of second and fourth number is 10.
For a sequence Sn = 4(7n – 1), verify whether the sequence is a G.P.
In a G.P., if t2 = 7, t4 = 1575, find r.
Find k so that k – 1, k, k + 2 are consecutive terms of a G.P.
Verify whether the following sequence is G.P. If so, find `"t"_n`
`sqrt5, 1/sqrt5, 1/(5sqrt5), 1/(25sqrt5),` ....
If for a sequence, `t_n = 5^(n-3)/2^(n-3)`, show that the sequence is a G.P.
Find its first term and the common ratio.
Verify whether the following sequence is G.P. If so, find tn.
`sqrt5,1/sqrt5,1/(5sqrt5),1/(25sqrt5),...`
Verify whether the following sequence are G.P. If so, find tn
`sqrt5, 1/sqrt5, 1/(5sqrt5), 1/(25sqrt5),.......`
For the G.P. if a = `2/3`, t6 = 162, find `r`
Verify whether the following sequence is G.P. If so, find tn.
`sqrt(5), 1/sqrt(5), 1/(5sqrt(5)), 1/(25sqrt(5)), ...`
If for a sequence, `t_n = (5^(n - 3))/(2^(n - 3))`, show that the sequence is a G.P.
Find its first term and the common ratio.
Verify whether the following sequence is G.P. If so, find tn.
`sqrt5,1/(sqrt5),1/(5sqrt5), 1/(25sqrt5)`, ......
