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प्रश्न
For the hyperbola 9x2 – 16y2 = 144, find the vertices, foci and eccentricity
उत्तर
The equation of the hyperbola can be written as `x^2/16 - y^2/9` = 1
So a = 4,
b = 3
And 9 = 16 (e2 – 1)
So that e2 = `9/16 + 1 = 25/16`
Which gives e = `5/4`.
Vertices are (± a, 0) = (± 4, 0)
And foci are (± ae, 0) = (± 5, 0).
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