Question

For the reaction,

\[\ce{2NO(g) + O2(g) -> 2NO2(g) ->[d(NO2)][dt] = 0.052 mol dm^{-3} s^{-1}}\]

Calculate rate of consumption of NO (g).

पर्याय

• 0.052 mol dm^-3 s^-1

• 0.114 mol dm^-3 s^-1

• 0.026 mol dm^-3 s^-1

• 0.078 mol dm^-3 s^-1

Answer 1

0.052 mol dm^-3 s^-1 

Explanation:

In the given reaction, the rate of consumption of NO = rate of formation of NO₂

So, `(- "d"["NO"])/"dt" = (+ "d"["NO"_2])/"dt"`

`(- 1)/2 "d" (["NO"])/"dt" = 1/2 ("d"["NO"_2])/"dt"`

`(- "d"["NO"])/"dt" = 2/2 ("d"["NO"_2])/"dt"`

`(- "d"["NO"])/"dt" = 0.052` mol dm^-3 s^-1