Question

For the stationary wave,

y = 8sin(6.25πx) cos(96πt) metre, the distance between a node and the next antinode is ____________.

पर्याय

• 17. 5 cm

• 1.5 m

• 6.25 m

• 4 cm

Answer 1

For the stationary wave,

y = 8sin (6.25πx) cos (96πt) metre, the distance between a node and the next antinode is 4 cm.

Explanation:

`"Comparing with standard stationary wave equation, we get"`

` (2pi"x")/lambda = 6.25  pi"x" Rightarrow lambda = 0.32  "m"`

`therefore  lambda/8 = 0.32/8 = 0.04  "m" = 4 "m"`