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प्रश्न
Form a continuous frequency distribution table for the marks obtained by 30 students in a X std public examination.
328, 470, 405, 375, 298, 326, 276, 362, 410, 255, 391, 370, 455, 229, 300, 183, 283, 366, 400, 495, 215, 157, 374, 306, 280, 409, 321, 269, 398, 200
उत्तर
Maximum mark obtained = 495
Minimum marks obtained = 157
Range = Maximum value – Minimum value
Range = 495 – 157
= 338
If we take the class size as 50 then the number of class intervals possible
= `"Range"/"Class size"`
= `338/50`
= 6.76 ≅ 7
| Class Intervals | Tally marks | Frequency |
| 150 - 200 | || | 2 |
| 200 - 250 | ||| | 3 |
| 250 - 300 | |||| | | 6 |
| 300 - 350 | |||| | 5 |
| 350 - 400 | |||| || | 7 |
| 400 - 450 | |||| | 4 |
| 450 - 500 | ||| | 3 |
| Total | 30 | |
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