Advertisements
Advertisements
प्रश्न
From 25 identical cards, numbered 1, 2, 3, 4, 5, ......, 24, 25; one card is drawn at random. Find the probability that the number on the card drawn is a multiple of 3.
उत्तर
There are 25 cards from which one card is drawn.
Total number of elementary events = n(S) = 25
From number 1 to 25, there are 8 number which are multiple of 3 i.e. {3, 6, 9, 12, 15, 18, 21, 24}
Favorable number of events = n(E) = 8
Probability of selecting a card with a multiple of 3 = `(n(E))/(n(S)) = 8/25`
APPEARS IN
संबंधित प्रश्न
Nine cards (identical in all respects) are numbered 2 to 10. A card is selected from them at random. Find the probability that the card selected will be an even number.
Hundred identical cards are numbered from 1 to 100. The cards are well shuffled and then a card is drawn. Find the probability that the number on the card drawn is a multiple of 6.
Hundred identical cards are numbered from 1 to 100. The cards are well shuffled and then a card is drawn. Find the probability that the number on the card drawn is greater than 85.
If two coins are tossed once, what is the probability of getting both heads or both tails.
A bag contains 16 coloured balls. Six are green, 7 are red and 3 are white. A ball is chosen, without looking into the bag. Find the probability that the ball chosen is white.
A ball is drawn at random from a box containing 12 white, 16 red and 20 green balls. Determine the probability that the ball drawn is not green.
A bag contains 3 red balls, 4 blue balls and 1 yellow ball, all the balls being identical in shape and size. If a ball is taken out of the bag without looking into it; find the probability that the ball is yellow.
Which of the following cannot be the probability of an event?
0.82
Which of the following cannot be the probability of an event?
–2.4
A card is drawn from a well-shuffled pack of 52 playing cards. Find the probability of the event, the card drawn is a red card.
Solution:
Suppose ‘S’ is sample space.
∴ n(S) = 52
Event A: Card drawn is a red card.
∴ Total red cards = `square` hearts + 13 diamonds
∴ n(A) = `square`
∴ p(A) = `square/("n"("s"))` ....formula
∴ p(A) = `26/52`
∴ p(A) = `square`
