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प्रश्न
Given log5 y = n. Express 53n + 2 in terms of y.
बेरीज
उत्तर
log5 y = n
5n = y
Consider 5n = y
⇒ `(5^n)^3=y^3`
⇒ `5^(3n)=y^3`
⇒ `5^(3n) xx 5^2 = y^3 xx 5^2`
⇒` 5^(3n+2) = 25y^3`
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Interchanging Logarithmic and Exponential Forms
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