Advertisements
Advertisements
प्रश्न
Given that ∆H = 0 for mixing of two gases. Explain whether the diffusion of these gases into each other in a closed container is a spontaneous process or not?
उत्तर
It is a spontaneous process. Although enthalpy change is zero, randomness or disorder (ΔS) increases and ΔS is positive. Therefore, in the equation, ΔG = ΔH – TΔS, the term TΔS will be negative. Hence ΔG will be negative.
APPEARS IN
संबंधित प्रश्न
Which of the following is not correct?
Identify the state and path functions out of the following:
- Enthalpy
- Entropy
- Heat
- Temperature
- Work
- Free energy
Which of the following is NOT correct?
For the reaction, \[\ce{X2O_{4(l)} -> 2XO_{2(g)}}\] ΔU = 2.1 kcal, ΔS = 20 cal K–1 at 300 K Hence: ΔG is:
For the cell process:
\[\ce{Sn(s) + Pb^{+2}(aq) -> Pb(s) + Sn^{+2}(aq)}\]
The ratio of Pb+2 to Sn+2 ion concentration for spontaneity is ______.
Given: `"E"_("Sn"^(2+)//"Sn")^0` = − 0.136 V, `"E"_("Pb"^(2+)//"Pb")^0` = − 0.126 V
