Question

Henry's law constant for a gas CH₃Br is 0.159 mol dm⁻³ atm⁻¹ at 25°C the solubility of CH₃Br in water at 25°C and a partial pressure of 0.164 atm ____________.

पर्याय

• 0.0159 mol dm⁻³

• 0.164 mol dm⁻³

• 0.026 mol dm⁻³

• 0.042 mol dm⁻³

Answer 1

Henry's law constant for a gas CH₃Br is 0.159 mol dm⁻³ atm⁻¹ at 25°C the solubility of CH₃Br in water at 25°C and a partial pressure of 0.164 atm 0.026 mol dm⁻³.

Explanation:

S = K_HP = 0.159 mol dm⁻³ atm⁻¹ × 0.164 atm

= 0.026 mol dm⁻³