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प्रश्न
how can demineralised be obtained?
उत्तर
Demineralised water is obtained by passing water successively through a cation exchange (in the H+ form) and an anion exchange (in the OH– form) resin.
During the cation exchange process, H+ exchanges for Na+, Mg2+, Ca2+, and other cations present in water.
\[\ce{2RH_{(s)} + M^{2+}_{(aq)} ⇌ MR_{2(s)} + 2H^+_{(aq)}}\] ....(1)
In the anion exchange process, OH– exchanges for anions such as
\[\ce{CO^{2-}_3, SO^{2-}_4, Cl^-, HCO^-_3}\] etc. present in water.
\[\ce{RNH_{2(s)} + H_2O_{(l)} <=> RNH^+_3 . OH^-_{(s)}}\]
\[\ce{RNH^+_3OH^-_{(s)} + X^-_{(aq)} ⇌ RNH^+_3 . X^-_{(s)} + OH^-_{(aq)}}\] ....(2)
OH– ions liberated in reaction (2) neutralize H+ ions liberated in reaction (1), thereby forming water.
\[\ce{H^+_{(aq)} + OH^-_{(aq)} -> H_2O_{(l)}}\]
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संबंधित प्रश्न
What is meant by ‘demineralised’?
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When sodium peroxide is treated with dilute sulphuric acid, we get ______.
Which of the following ions will cause hardness in water sample?
Which of the following compounds is used for water softening?
Complete the following equations:
\[\ce{PbS (s) + H2O2 (aq) ->}\]
Complete the following equations:
\[\ce{CO (g) + 2H2 (g) ->[Cobalt][Catalyst]}\]
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Match the items in Column I with the relevant item in Column II.
Column I | Column II |
(i) Hydrogen peroxide is used as a | (a) zeolite |
(ii) Used in Calgon method | (b) perhydrol |
(iii) Permanent hardness of hard water is removed by | (c) sodium hexametaphosphate |
(d) propellant |
Assertion (A): Permanent hardness of water is removed by treatment with washing soda.
Reason (R): Washing soda reacts with soluble magnesium and calcium sulphate to form insoluble carbonates.
Which one of the following methods is most suitable for preparing deionized water?
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