Advertisements
Advertisements
प्रश्न
How many point of discontinuity for the following function for x ∈ R
`f(x) = {{:(x + 1",", if x ≥ 1),(x^2 + 1",", if x < 1):}`
पर्याय
4
3
1
0
MCQ
उत्तर
0
Explanation:
At `x` = 1, L.H.L = `lim_(x -> 1) f(x) = lim_(x -> 1) (x^2 + 1)` = 2
R.H.L = `lim_(x -> 1^+) f(x) = lim_(x -> 1^+) (x + 1)` = 2
`f(1)` = 1 + 1 = 2
⇒ `f` is continuous at `x` = C > 1
At `x` = C > 1,
`lim_(x -> C) f(x) = lim_(x -> C) (x + 1) = C + 1 = f(C)`
⇒ `f` is continuous at `x` = C > 1
At `x` = C > 1,
`lim_(x -> C) f(x) = lim_(x -> C) (x^2 + 1) = C^2 + 1 = f(C)`
⇒ `f` is continuous at `x` = C < 1
There is no point of discontinuity at any point x ∈ R.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?