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प्रश्न
How will you prepare propanone (acetone) from Grignard reagent?
थोडक्यात उत्तर
उत्तर
Grignard reagent (methyl magnesium iodide) reacts with cadmium chloride to give dimethyl cadmium. When acetyl chloride reacts with dimethyl cadmium, propanone (acetone) is obtained.
\[\ce{2CH3MgI + CdCl2 -> (CH3)2Cd + 2Mg(I) Cl}\]
\[\ce{\underset{Acetyl chloride}{2CH3 - COCl} + \underset{cadmium}{\underset{Dimethyl}{(CH3)2}}Cd -> \underset{(Acetone)}{\underset{Propanone}{2CH3 - CO}} - CH3 + CdCl2}\]
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