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प्रश्न
Identify the type of reaction taking place in the following case and write the balanced chemical equation for the reaction.
Potassium iodide reacts with lead nitrate to produce potassium nitrate and lead iodide.
उत्तर
The given reaction is a double displacement reaction.
\[\ce{2Kl(aq) + Pb(NO3)2(aq)->2KNO3(aq) + Pbl2(s)}\]
संबंधित प्रश्न
When the substance ‘A’ is added to a solution of BaSO4, a yellow precipitate is formed.
- What do you think substance A is likely to be?
- Name the precipitate.
- Which type of reaction is this?
What is meant by double displacement reaction? Explain with help of one example.
A red-brown metal X forms a salt XSO4. When hydrogen sulphide gas is passed through an aqueous solution of XSO4, then a black precipitate of XS is formed alongwith sulphuric acid solution.
(a) What could the salt XSO4 be?
(b) What is the colour of salt XSO4?
(c) Name the black precipitate XS.
(d) By using the formula of the salt obtained in (a) above, write an equation of the reaction which takes place when hydrogen sulphide gas is passed through its aqueous solution.
(e) What type of chemical reaction takes place in this case?
The aqueous solutions of copper sulphate and zinc sulphate appear
(A) blue and green respectively
(B) green and colourless respectively
(C) blue and brown respectively
(D) blue and colourless respectively.
When a potassium iodide solution is added to a solution of lead (II) nitrate in a test tube, a precipitate is formed.
List two types of reactions in which this reaction can be placed.
Differentiate between displacement reaction and a neutralization reaction.
In a double displacement reaction ______.
Identify the product which represents the solid state in the above reaction.
A chemical reaction in which exchange of ions occurs between the reactants is known as ______.
Write the method of preparation of Ca(OH)2. What happens when CO2 is passed through it? Write balanced chemical equation for the reaction involved.
