Question

If 1 g of a steam which is at 100°C starts melting then how much ice will remain at 0° C? (Latent heat of ice = 80 cal/g and latent heat of steam= 540 cal/g)

पर्याय

• 1 g

• 2 g

• 4 g

• 8 g

Answer 1

8 g

Explanation:

Suppose m g ice is melted, then beat required for its melting

= mL = m x 80 cal

Heat available with steam for being condensed and then brought to 0° C

= 1 x 540 + 1 x 1 x (100 - 0) = 640 cal

`Rightarrow "Heat Jost= Heat taken"`

`Rightarrow 640 = "m" xx 80 Rightarrow "m" = 8  "g"`