Question

If (1 – p) is a root of the equation x² + px + 1 – p = 0, then roots are:

पर्याय

• 0, 1

• –1, 1

• 0, –1

• –1, 2

Answer 1

0, –1

Explanation:

(1 – p) is a root.

∴ (1 – p)² + p(1 – p) + 1 – p = 0

⇒ (1 – p) (1 – p + p + 1) = 0

⇒ (1 – p) (2) = 0

⇒ p = 1

x² + x = 0

One root = 0 and another root = – 1

∴ Roots are 0 and – 1.