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प्रश्न
If 2 sin (A + B) = `sqrt3` and cos (A − B) = 1, then find the measures of angles A and B. 0 ≤ A, B, (A + B) ≤ 90°.
बेरीज
उत्तर
2 sin (A + B) = `sqrt3`
⇒ sin (A + B) = `sqrt3/2`
⇒ sin (A + B) + sin 60
A + B = 60 ...(i)
cos (A − B) = 1
cos (A B) = cos 0
A − B = 0 ...(ii)
Adding (i) and (ii)
2A = 60
A = 30°
From (i)
30 + B = 60
B = 30°
∠A = 30°, ∠B = 30°
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