Question

If `[(2, 0, 7),(0, 1, 0),(1, -2, 1)] [(-x, 14x, 7x),(0, 1, 0),(x, -4x, -2x)] = [(1, 0, 0),(0, 1, 0),(0, 0, 1)]`then find the value of x

पर्याय

• `1/2`

• `1/5`

• No unique value of ‘x’

• None of these

Answer 1

`bb(1/5)`

Explanation:

We have `[(2, 0, 7),(0, 1, 0),(1, -2, 1)]`

`[(-x, 14x, 7x),(0, 1, 0),(x, -4x, -2x)] = [(5x, 0, 0),(0, 1, 0),(0, 10x - 2, 5x)] = [(1, 0, 0),(0, 1, 0),(0, 0, 1)]`

`\implies` x = `1/5`