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प्रश्न
If `θ∈[(5π)/2, 3π]` and 2cosθ + sinθ = 1, then the value of 7cosθ + 6sinθ is ______.
पर्याय
4.00
5.00
6.00
7.00
MCQ
रिकाम्या जागा भरा
उत्तर
If `θ∈[(5π)/2, 3π]` and 2cosθ + sinθ = 1, then the value of 7cosθ + 6sinθ is 6.00.
Explanation:
2cosθ + 1 – sinθ
4cos2θ = 1 + sin2θ – 2sinθ
4 – 4sin2θ = 1 + sin2θ – 2sinθ
5sin2θ – 2sinθ – 3 = 0
(5sinθ + 3)(sinθ – 1) = 0
sinθ = 1, as `θ∈[(5π)/2, 3π]`
So, cosθ = 0
Now, 7cosθ + 6sinθ = 6
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