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If a, b, c are in geometric progression, and if abCa1x=b1y=C1z, then prove that x, y, z are in arithmetic progression - Mathematics

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प्रश्न

If a, b, c are in geometric progression, and if `"a"^(1/x) = "b"^(1/y) = "C"^(1/z)`, then prove that x, y, z are in arithmetic progression

बेरीज

उत्तर

Given a, b, c are in G.P.

⇒ b2 = ac

⇒ log b2 = log ac

(i.e.) 2log b = log a + log c  .....(1)

We are given `"a"^(1/x) = "b"^(1/y) = "C"^(1/z)` = k ......(say)

⇒ log ak = `1/x`

log bk = `1/y`

log ck = `1/z`

⇒ log ak = `1/x`

⇒ x = log ka

y = log kb

z = log kc

Substituting these values in equation (1) we get

2y = x + z

⇒ x, y z are in A.P.

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Finite Sequences
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Binomial Theorem, Sequences and Series - Exercise 5.2 [पृष्ठ २१८]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 5 Binomial Theorem, Sequences and Series
Exercise 5.2 | Q 7 | पृष्ठ २१८

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