मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता १०

If a, b, c is three consecutive terms of an A.P. and x, y, z are three consecutive terms of a G.P. then prove that xb–c × yc–a × za–b = 1 - Mathematics

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प्रश्न

If a, b, c is three consecutive terms of an A.P. and x, y, z are three consecutive terms of a G.P. then prove that xb–c × yc–a × za–b = 1

बेरीज

उत्तर

a, b, c is three consecutive terms of an AP.

∴ Let a, b, c be a, a + d, a + 2d respectively  ...(1)

x, y, z is three consecutive terms of a GP.

∴ Assume x, y, z as x, x.r, x.r2 respectively  ...(2)

PT : xb–c, yc–a, za–b = 1

Substituting (1) and (2) in L.H.S., we get

L.H.S. = `x^("a" + "d" - "a" - 2"d") xx (x"r")^("a" + 2"d" - "a") xx (x"r"^2)^("a" - "a" - "d")`

= (x)d . (xr)2d (xr2)–d 

= `1/x^4 xx x^(2"d") *  "r"^(2"d") xx 1/(x^"d" "r"^(2"d")` = 1 = R.H.S.

Hence proved.

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पाठ 2: Numbers and Sequences - Exercise 2.7 [पृष्ठ ७३]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
पाठ 2 Numbers and Sequences
Exercise 2.7 | Q 12 | पृष्ठ ७३
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