Advertisements
Advertisements
प्रश्न
If a2 + b2 + c2 = 250 and ab + bc + ca = 3, find a + b + c.
उत्तर
Recall the formula
`(a+b+c)^2 = a^2 +b^2 +c^2 + 2(ab + bc + ca)`
Given that
`a^2 + b^2 + c^2 = 250 , ab + bc + ca = 3 `
Then we have
`(a+b+c)^2 = a^2 + b^2 + c^2 + 2 (ab + bc+ca)`
`(a+b+c)^2 = 250 + 2.(3)`
`(a+b+c)^2 = 256`
`(a+b+c) =± 16`
APPEARS IN
संबंधित प्रश्न
Get the algebraic expression in the following case using variables, constants and arithmetic operations.
One-fourth of the product of numbers p and q.
Factorize a2 + 4b2 - 4ab - 4c2
What must be added to the following expression to make it a whole square?
4x2 − 12x + 7
Write the value of 253 − 753 + 503.
(x + y)3 − (x − y)3 can be factorized as
Multiply: (2x + 5y + 6)(3x + y - 8)
Divide: 8x + 24 by 4
Divide: 4a2 - a by - a
Write the coefficient of x2 and x in the following polynomials
`6 - 2x^2 + 3x^3 - sqrt(7)x`
If x = 2 and y = 3, then find the value of the following expressions
x + y