Advertisements
Advertisements
प्रश्न
If 'α' and 'β' are the maximum velocity and maximum acceleration respectively, of a particle performing linear simple harmonic motion, then the path length of the particle is _______.
पर्याय
`(2alpha)^2/beta`
`(2beta)^2/alpha`
`(2alpha)/beta`
`alpha/beta`
MCQ
रिकाम्या जागा भरा
उत्तर
If 'α' and 'β' are the maximum velocity and maximum acceleration respectively, of a particle performing linear simple harmonic motion, then the path length of the particle is `underline((2alpha)^2/beta)`.
Explanation:
α = Aω
β = Aω2
Path length = 2A
α2 = A2ω2
β = Aω2
A = `alpha^2/beta`
`therefore "2A" = (2alpha^2)/beta`
shaalaa.com
Acceleration (a), Velocity (v) and Displacement (x) of S.H.M.
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
