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प्रश्न
If cos θ = `15/17` then find sin θ.
बेरीज
उत्तर
sin2θ + cos2θ = 1
⇒ sin2θ + `(15/17)^2 = 1 ...( cos θ = 15/17)`
⇒ sin2θ + `225/289` = 1
⇒ sin2θ = `1 - 225/289`
⇒ sin2θ = `(289 - 225)/289`
⇒ sin2θ = `64/289`
⇒ sin θ = `sqrt (64/289)` ...(Taking square root of both sides)
⇒ sin θ = `8/17`
Thus, the value of sin θ is `8/17`.
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Trigonometric Ratios of 30° and 60° Angles
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