Question

If f(x) = `3cos(x + (5π)/6) - 5sinx + 2`, then maximum value of f(x) is ______.

पर्याय

• 6.00

• 7.00

• 8.00

• 9.00

Answer 1

If f(x) = `3cos(x + (5π)/6) - 5sinx + 2`, then maximum value of f(x) is 9.00.

Explanation:

f(x) = `3(cosx cos  (5pi)/6-sinxsin  (5pi)/6)-5sinx+2`

f(x) = `-13/2sinx - (3sqrt(3))/2cosx + 2`

Range of f(x) = [–7, 7] + 2

= [–5, 9] < Max value = 9