Advertisements
Advertisements
प्रश्न
If the mean of 25 observations is 27 and each observation is decreased by 7, what will be new mean?
उत्तर
Mean of given observations =`"sun of given observations"/" total number of observations"`
Mean of 25 observations = 27
∴ Sum of 25 observations = 27 × 25 = 675
If 7 is subtracted from every number, then the sum = 675 – (25 × 7)
= 675 – 175
= 500
Then, new mean =`500/25` = 20
Thus, the new mean will be 20.
APPEARS IN
संबंधित प्रश्न
The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f.
Daily pocket allowance (in Rs | 11 - 13 | 13 - 15 | 15 - 17 | 17 - 19 | 19 - 21 | 21 - 23 | 23 - 25 |
Number of workers | 7 | 6 | 9 | 13 | f | 5 | 4 |
The mean of the following distribution is 18. Find the frequency f of class 19 – 21.
Class | 11-13 | 13-15 | 15-17 | 17-19 | 19-21 | 21-23 | 23-25 |
Frequency | 3 | 6 | 9 | 13 | f | 5 | 4 |
Find the value of p for the following distribution whose mean is 16.6
x | 8 | 12 | 15 | P | 20 | 25 | 30 |
f | 12 | 16 | 20 | 24 | 16 | 8 | 4 |
The following table gives the distribution of total household expenditure (in rupees) of manual workers in a city. Find the average expenditure (in rupees) per household.
Expenditure (in rupees) (x1) |
Frequency(f1) |
100 - 150 | 24 |
150 - 200 | 40 |
200 - 250 | 33 |
250 - 300 | 28 |
300 - 350 | 30 |
350 - 400 | 22 |
400 - 450 | 16 |
450 - 500 | 7 |
For the following distribution, calculate mean using all suitable methods:
Size of item | 1 - 4 | 4 - 9 | 9 - 16 | 16 - 27 |
Frequency | 6 | 12 | 26 | 20 |
The weekly observations on cost of living index in a certain city for the year 2004 - 2005 are given below. Compute the weekly cost of living index.
Cost of living Index | Number of Students |
1400 - 1500 | 5 |
1500 - 1600 | 10 |
1600 - 1700 | 20 |
1700 - 1800 | 9 |
1800 - 1900 | 6 |
1900 - 2000 | 2 |
The daily expenditure of 100 families are given below. Calculate `f_1` and `f_2` if the mean daily expenditure is ₹ 188.
Expenditure (in Rs) |
140-160 | 160-180 | 180-200 | 200-220 | 220-240 |
Number of families |
5 | 25 | `f_1` | `f_2` | 5 |
Find the mean of the following frequency distribution:
Class Interval | Frequency |
0 - 50 | 4 |
50 - 100 | 8 |
100 - 150 | 16 |
150 - 200 | 13 |
200 - 250 | 6 |
250 - 300 | 3 |
A frequency distribution of the life times of 400 T.V., picture tubes leased in tube company is given below. Find the average life of tube:
Life time (in hrs) | Number of tubes |
300 - 399 | 14 |
400 - 499 | 46 |
500 - 599 | 58 |
600 - 699 | 76 |
700 - 799 | 68 |
800 - 899 | 62 |
900 - 999 | 48 |
1000 - 1099 | 22 |
1100 - 1199 | 6 |
In calculating the mean of grouped data, grouped in classes of equal width, we may use the formula `barx = a + (sumf_i d_i)/(sumf_i)` where a is the assumed mean. a must be one of the mid-points of the classes. Is the last statement correct? Justify your answer.