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If one root of k(x − 1)2 = 5x − 7 is double the other root, show that k = 2 or −25 - Mathematics

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प्रश्न

If one root of k(x − 1)2 = 5x − 7 is double the other root, show that k = 2 or −25

बेरीज

उत्तर

The given quadratic equation is

k(x – 1)2 = 5x – 7

k(x2 – 2x + 1) – 5x + 7 = 0

kx2 – 2kx + k – 5x + 7 = 0

kx2 – (2k + 5)x + k + 7 = 0   ......(1)

Let the roots be α and 2α

Sum of the roots α + 2α = `- "b"/"a"`

3α = `-((-(2"k" +5))/"k")` 

3α = `(2"k" + 5)/"k"`

α = `(2"k" + 5)/(3"k")`   ......(2)

Product of te roots α(2α) = `"c"/"a"`

2 = `("k"+ 7)/"k"`

α2 = `("k" + 7)/(2"k")`  .....(3)

Using equation (2) and (3) we have

`((2"k" + 5)/(3"k"))^2 = ("k" + 7)/(2"k")`

`(4"k"^2 + 20"k" + 25)/(9"k"^2) = ("k" + 7)/(2"k")`

`(4"k"^2 + 20"k" + 25)/(9"k") = ("k" + 7)/(2)`

2(4k2 + 20k + 25) = 9k(k + 7)

8k2 + 40k + 50 = 9k2 + 63k

9k2 + 63k – 8k2 – 40k – 50 = 0

k2 + 23k – 50 = 0

k2 + 25k – 2k – 50 = 0

k(k + 25) – 2(k + 25) = 0

(k – 2) (k + 25) = 0

k – 2 = 0 or k + 25 = 0

k = 2 or k = – 25

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Quadratic Functions
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पाठ 2: Basic Algebra - Exercise 2.4 [पृष्ठ ६२]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 2 Basic Algebra
Exercise 2.4 | Q 4 | पृष्ठ ६२

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