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प्रश्न
If the point C (–1, 2) divides internally the line segment joining A (2, 5) and B in ratio 3 : 4, find the coordinates of B
बेरीज
उत्तर
Let the coordinates of B be (α, β). It is given that AC : BC = 3 : 4. So, the coordinates of C are
`( \frac{3\alpha +4\times 2}{3+4},\ \frac{3\beta +4\times 5}{3+4})=( \frac{3\alpha +8}{7},\ \frac{3\beta +20}{7})`
But, the coordinates of C are (–1, 2)
`\therefore \frac{3\alpha +8}{7}=-1\text{ and }\frac{3\beta +20}{7}=2`
⇒ α = – 5 and β = – 2
Thus, the coordinates of B are (–5, –2).
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