मराठी

If r is the radius of spherical balloon at time t and the surface area of balloon changes at a constant rate K, then ______. -

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प्रश्न

If r is the radius of spherical balloon at time t and the surface area of balloon changes at a constant rate K, then ______.

पर्याय

  • `4pi"r"^2 = "Kt"^2/2 + "c"`

  • 8πr2 = Kt + c

  • `pi"r"^2 = "Kt"^2/2 + "c"`

  • 4πr2 = Kt + c

MCQ
रिकाम्या जागा भरा

उत्तर

If r is the radius of spherical balloon at time t and the surface area of balloon changes at a constant rate K, then 4πr2 = Kt + c.

Explanation:

According to question,

`"d"/"dx" (4pi"r"^2)` = K   (∵ surface area of spherical ballon with radius r is 4πr2)

`=> 4pi (2"r") "dr"/"dt" = "K" => 8pi"r"  "dr" = "Kdt"` 

On Integrating both sides, we get

`8pi int "r"  "dr" = "K" int "dt"`

`=> 8pi "r"^2/2 = "Kt" + "C"`

`= 4pi"r"^2 = "Kt" + "C"`

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Application of Differential Equations
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