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प्रश्न
If sinθ = `1/sqrt(2)` and `π/2 < θ < π`. Then the value of `(sinθ + cosθ)/tanθ` is ______.
पर्याय
0
1
`1/sqrt(2)`
`sqrt(2)`
MCQ
रिकाम्या जागा भरा
उत्तर
If sinθ = `1/sqrt(2)` and `π/2 < θ < π`. Then the value of `(sinθ + cosθ)/tanθ` is 0.
Explanation:
sinθ = `1/sqrt(2)` and `π/2 < θ < π`
then θ = `π - π/4 = (3π)/4`
So `(sinθ + cosθ)/tanθ = (sin (3π)/4 + cos (3π)/4)/(tan (3π)/4)`
= `(1/sqrt(2) - 1/sqrt(2))/(-1)`
= 0
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