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प्रश्न
If TC = 2.5q3 − 13q2 + 50q + 12 derive the MC function and AC function.
बेरीज
उत्तर
Given:
TC= 2.5q3 – 13q2 + 50q + 12
Marginal cost function
MC = `"d(TC)"/"dQ"`
= `"d"/"dq"` [2.5q3 – 13q2 + 50q + 12]
2.5 (3q2) – 13 (2q) + 50 (1) + 0
MC = 7.5q – 26q + 50
Average cost AC = `"TC"/"q"`
= `(2.5"q"^3 - 13"q"^2 + 50q+12)/"q"`
= `(2.5"q"^3)/"q"` - `(13"q"^2)/"q"` + `(50"q")/q`+ `12/"q"`
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