Question

If the 0.05 molar solution of m⁺ is replaced by a 0.0025 molar m⁺ solution, then the magnitude of the cell potential would be

पर्याय

• 3.5 mv

• 70 mv

• 140 mv

• 700 mv

Answer 1

140 mv

Explanation:

E cell = `E_(cell)^circ - 0.059/1  log  (0.0025/1)` = – 0.059

log (0.0025)

E(cells) = 70 mv

`"E cell"/(E_(cell)^circ) = (log  (0.0025))/(log  (0.05)) = (- 23)/(- 13)` = 2

E cell = 70 × 2 = 140 mv.