Advertisements
Advertisements
प्रश्न
If the common ratio of a G.P. is `2/3` and sum of its terms to infinity is 12. Find the first term.
उत्तर
r = `2/3` sum to infinity = 12 …[Given]
Sum to infinity = `"a"/(1 - "r")`
∴ 12 = `"a"/(1 - 2/3)`
∴ a = `12 xx 1/3`
∴ a = 4.
APPEARS IN
संबंधित प्रश्न
Determine whether the sum to infinity of the following G.P’.s exist. If exists, find it:
`1/2, 1/4, 1/8, 1/16`, ...
Determine whether the sum to infinity of the following G.P’.s exist. If exists, find it:
`2, 4/3, 8/9, 16/27`, ...
Determine whether the sum to infinity of the following G.P’.s exist. If exists, find it:
`-3, 1, (-1)/3, 1/9`, ...
Determine whether the sum to infinity of the following G.P’.s exist. If exists, find it:
`1/5, (-2)/5, 4/5, (-8)/5, 16/5`, ...
The sum of the terms of an infinite G.P. is 5 and the sum of the squares of those terms is 15. Find the G.P.
If the sum of an infinite GP be 9 and sum of first two terms be 5 then their common ratio is ______.
Find `sum_(r = 1) ^n (1 + 2 + 3 + ... + r)/r`
For the G.P
if a = `2/3 , t_6 = 162 ,"find r"`
Express the following recurring decimal as a rational number.
`3.dot5`
Express the following recurring decimal as a rational number.
`3.4 bar56`
Express the following recurring decimal as a rational number.
`3.4 bar56`
Express the following recurring decimals as a rational number:
`3.dot5`
Express the following recurring decimals as a rational number.
`3.4overline56`
