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प्रश्न
If the foot of perpendicular drawn from the origin to the plane is (3, 2, 1), then the equation of plane is ____________.
पर्याय
3x + 2y − z = 12
3x − 2y − z = 12
3x + 2y − z = 14
3x + 2y + z = 14
MCQ
रिकाम्या जागा भरा
उत्तर
If the foot of perpendicular drawn from the origin to the plane is (3, 2, 1), then the equation of plane is 3x + 2y + z = 14.
Explanation:
P(3, 2, 1) denotes the perpendicular's foot of a line traced from the starting point to the plane.
∴ OP is perpendicular to the plane.
As a result, the normal to the plane's direction ratio is (3, 2, 1)
Now that the plane has passed through (3, 2, 1)
∴ It equation is 3(x − 3) + 2(y − 2) + 1(z − 1) = 0
3x − 9 + 2y − 4 + z − 1 = 0
3x + 2y + z = 14
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