Question

If the replacement set is the set of real numbers, solve:

8 – 3x ≤ 20

Answer 1

8 – 3x ≤ 20

– 3x ≤ 20 – 8

– 3x ≤ 12

3x ≥ – 12

${\displaystyle x\ge \frac{-12}{3}}$

x ≥ – 4

Since the replacement set of real numbers.

∴ Solution set = {x : x ∈ R and x ≥ – 4}