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प्रश्न
If the roots of the equations ax2 + 2bx + c = 0 and `"bx"^2 - 2sqrt"ac" "x" + "b" = 0` are simultaneously real, then
पर्याय
b = ac
b2 = ac
a2 = bc
c2 = ab
MCQ
उत्तर
b2 = ac
Explanation:
Given equations have real roots, then
D1 ≥ 0 and D2 ≥ 0
(2b)2 – 4ac ≥ 0 and `(-2sqrt"ac")^2 - 4"b"."b"` ≥ 0
4b2 – 4ac ≥ 0 and 4ac – 4b2 ≥ 0
b2 ≥ ac and ac ≥ b2
⇒ b2 = ac
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